leetcode-129 Sum Root to Leaf Numbers
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DFS的题目好像都是用递归
遇到递归的时候,把终止条件,各种条件想清楚就可以大胆写了,可以先举几个简单的例子帮助
<span style="font-family:Microsoft YaHei;font-size:14px;">/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public: int sumNumbers(TreeNode *root) { if(root == NULL) return 0; int sum = 0; return helper(root,sum); } int helper(TreeNode *node,int sum){ if(node->left == NULL && node->right == NULL) return sum * 10 + node->val; int val = 0; if(node->left != NULL) val += helper(node->left,sum * 10 + node->val); if(node->right != NULL) val += helper(node->right,sum * 10 + node->val); return val; }};</span>
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