FZU 1004----Number Triangle

Description

Consider the number triangle shown below. Write a program that calculates the highest sum of numbers that can be passed on a route that starts at the top and ends somewhere on the base. Each step can go either diagonally down to the left or diagonally down to the right.

7 3 8 8 1 0 2 7 4 44 5 2 6 5

In the sample above, the route from 7 to 3 to 8 to 7 to 5 produces the highest sum: 30.

Input

There are multiple test cases.The first line of each test case contains R (1 <= R <= 1000), the number of rows. Each subsequent line contains the integers for that particular row of the triangle. All the supplied integers are non-negative and no larger than 100.

Output

Print a single line containing the largest sum using the traversal specified for each test case.

Sample Input

573 88 1 02 7 4 44 5 2 6 5

Sample Output

30

#include<stdio.h>int a[1005][1005],dp[1005][1005];int max(int a,int b){   return a>b?a:b;}int main(void){int i,j,n;while(scanf("%d",&n)!=EOF){for(i=0;i<n;i++){for(j=0;j<=i;j++){scanf("%d",&dp[i][j]);}}for(i=n-2;i>=0;i--){for(j=0;j<=i;j++){dp[i][j]=dp[i][j]+max(dp[i+1][j],dp[i+1][j+1]);}}printf("%d\n",dp[0][0]);}return 0;}