【动态树】[BZOJ2002] Bounce 弹飞绵羊
来源:互联网 发布:安顺行知高中地址 编辑:程序博客网 时间:2024/05/16 01:30
实际上就是动态树的模版加上一个维护每一条链的size这样就可以吧一次弹射看成一条路径,然后统计这个路径上的size实际上就是经过了多少个节点然后没什么了。。
#include <bits/stdc++.h>using namespace std;const int MAXN = 200000;int ch[MAXN+10][2], Fa[MAXN+10];int que[MAXN+10], sz[MAXN+10];bool rev[MAXN+10];bool isroot(int u){return ch[Fa[u]][0] != u && ch[Fa[u]][1] != u;}void Rotate(int u){ int x = Fa[u], y = Fa[x]; bool md = ch[x][1] == u; Fa[u] = y; if(!isroot(x)) ch[y][ch[y][1] == x] = u; ch[x][md] = ch[u][!md]; Fa[ch[u][!md]] = x; ch[u][!md] = x; Fa[x] = u; sz[x] = sz[ch[x][0]] + sz[ch[x][1]] + 1;}void push_down(int u){ if(rev[u]){ rev[u] ^= 1; rev[ch[u][0]] ^= 1; rev[ch[u][1]] ^= 1; swap(ch[u][0], ch[u][1]); }}void Splay(int u){ int now = u; que[0] = 1; que[1] = now; while(!isroot(now)){ que[++que[0]] = Fa[now]; now = Fa[now]; } for(;que[0];que[0]--) push_down(que[que[0]]); while(!isroot(u)){ int x = Fa[u], y = Fa[x]; if(!isroot(x)){ if((ch[x][0] == u) ^ (ch[y][0] == x)) Rotate(u); else Rotate(x); } Rotate(u); } sz[u] = sz[ch[u][0]] + sz[ch[u][1]] + 1;}void access(int u){ int up = 0; while(u != 0){ Splay(u); ch[u][1] = up; up = u; u = Fa[u]; }}void root(int u){ access(u); Splay(u); rev[u] ^= 1;}void Link(int x, int y){ root(x); Fa[x] = y; Splay(x);}void Cut(int x, int y){ root(x); access(y); Splay(y); ch[y][0] = Fa[x] = 0;}/*bool Query(int x, int y){ access(x); Splay(x); int u = x; while(ch[u][0]) u = ch[u][0]; access(y); Splay(y); int u1 = y; while(ch[u1][0]) u1 = ch[u1][0]; return u == u1;}*/int Jp[MAXN+10];int main(){ int n, m, a, b; scanf("%d", &n); for(int i=1;i<=n;i++){ scanf("%d", &a); Jp[i] = min(i+a, n+1); Link(Jp[i], i); } int ord; scanf("%d", &m); for(int i=0;i<m;i++){ scanf("%d", &ord); if(ord == 1){ scanf("%d", &a); root(n+1); access(a+1); Splay(a+1); printf("%d\n", sz[ch[a+1][0]]); } else{ scanf("%d %d", &a, &b); Cut(a+1, Jp[a+1]); Jp[a+1] = a + 1 + b; if(a + b + 1 > n) Jp[a+1] = n+1; Link(Jp[a+1], a+1); } } return 0;}
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