Lowest Common Multiple Plus
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Lowest Common Multiple Plus
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 39514 Accepted Submission(s): 16312
Problem Description
求n个数的最小公倍数。
Input
输入包含多个测试实例,每个测试实例的开始是一个正整数n,然后是n个正整数。
Output
为每组测试数据输出它们的最小公倍数,每个测试实例的输出占一行。你可以假设最后的输出是一个32位的整数。
Sample Input
2 4 63 2 5 7
Sample Output
1270
Author
lcy
Source
C语言程序设计练习(五)
import java.util.*;class Main{ public static void main(String args[]){ Scanner sc =new Scanner(System.in); while(sc.hasNext()){ int n=sc.nextInt(); int [] a=new int[n]; for(int i=0;i<n;i++){ a[i]=sc.nextInt(); } int k=0; for(int i=0;i<n-1;i++){ for(int j=a[i];j<=a[i]*a[i+1];j++){ if(j%a[i]==0&&j%a[i+1]==0){ k=j; a[i+1]=k; break; } } } System.out.println(k); } }}
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