shell脚本编程(快速排序)

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#!/bin/bash#shell脚本编程之快速排序的实现(以最右边为元点的思想)a=(8 5 10 3 2 93 4 1 2 3 40 9 61 8 6 29)#a=(0  0  0  0  1  2  3  3  4  4  8  28  30495  921  43716)temp=buff=#交换函数swap(){buff=${a[$1]}a[$1]=${a[$2]}a[$2]=$buff}fun(){i=$(($1-1))j=$1temp=${a[$2]}if test $1 -ge $2 ;thenreturn 2 fiwhile [ $j -le $2 ];do[ $j -lt $2 ] && while [[ ${a[$j]} -gt $temp ]] ;do j=$(($j+1))donei=$(($i+1))swap $i $jj=$(($j+1))done fun 0 $(($i-1)) fun $(($i+2)) $2}fun 0 15for((i=0;i<16;i++)){echo -n ${a[$i]} " "}echoexit 0

下面是C++快速排序的对照代码

#include <iostream>using namespace std;void swap(int *a,int *b){int temp = *a;*a = *b;*b = temp;}void Grial(int a[],int x,int y){int i=x-1;int j=x;if(x>=y)return;int temp = a[y];while(j<=y){while(j<y&&a[j]>a[y])j++;i++;swap(&a[i],&a[j]);j++;}Grial(a,0,i-1);Grial(a,i+1,y);}int main(){int a[]={4,3,921,30495,28,43716,3,4,0,0,2,0,0,1,8,5};Grial(a,0,14);for(int i=0;i<15;i++){cout<<a[i]<<"  ";}cout<<endl;}

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