[POJ] 1004 -> Financial Management
来源:互联网 发布:图象处理算法 编辑:程序博客网 时间:2024/06/06 04:07
Financial Management
Time Limit: 1000MS Memory Limit: 10000KTotal Submissions: 159085 Accepted: 60480
Description
Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and solve his financing problems. The first step is to figure out what's been going on with his money. Larry has his bank account statements and wants to see how much money he has. Help Larry by writing a program to take his closing balance from each of the past twelve months and calculate his average account balance.
Input
The input will be twelve lines. Each line will contain the closing balance of his bank account for a particular month. Each number will be positive and displayed to the penny. No dollar sign will be included.
Output
The output will be a single number, the average (mean) of the closing balances for the twelve months. It will be rounded to the nearest penny, preceded immediately by a dollar sign, and followed by the end-of-line. There will be no other spaces or characters in the output.
Sample Input
100.00489.1212454.121234.10823.05109.205.271542.25839.1883.991295.011.75
Sample Output
$1581.42
Code:
#include <iostream>using namespace std;int main(){float n, sum = 0;for(int i = 0; i < 12; i++){cin >> n;sum += n;}printf("$%.2f\n", sum / 12);return 0;}
0 0
- 【POJ】1004 Financial Management
- POJ-1004:Financial Management
- POJ 1004 Financial Management
- POJ 1004 Financial Management
- [POJ]1004 Financial Management
- POJ 1004 Financial Management
- poj 1004 Financial Management
- poj 1004 Financial Management
- POJ-1004-Financial Management
- poj 1004 Financial Management
- POJ 1004 Financial Management
- [POJ][1004]Financial Management
- POJ 1004 Financial Management
- POJ 1004 Financial Management
- poj 1004 Financial Management
- poj 1004 Financial Management
- POJ 1004 - Financial Management
- POJ-1004 Financial Management
- <? super T>与<? extends T>区别
- 上拉电阻和下拉电阻的作用
- 黑马程序员Java----IO
- 2015腾讯暑期实习前端面试小结
- NSInteger取值范围
- [POJ] 1004 -> Financial Management
- HDU 2094产生冠军(拓扑排序)
- Linux常用命令-文件处理命令-文件处理命令
- 用数组实现的队列
- 判断app是否是在chrome上运行
- POI设置EXCEL单元格格式为文本、小数、百分比、货币、日期、科学计数法和中文大写
- p122 .10. 三角形面积
- Reverse Bits
- HttpClient实例