MVC与webservice上传文件（图片和视频），希望帮且到一些朋友

来源：互联网发布：那年那兔那些事儿知乎编辑：程序博客网时间：2024/04/28 01:51

最近做一个项目，要把图片和视频传到服务器上（网站与图片服务器分开），在网上找了好久，没找到完整的资料。

自己也折腾了半天，才把完整的代码实现完。可能好多朋友都有实现过，没分享代码吧，写得不好希望不要见笑！！

下面贴代码吧：首先MVC代码：

public string UploadVide()        {            string requesturl = "";            string result = "video/Videoitem/";            HttpFileCollectionBase fileToUpload = Request.Files;            foreach (string file in fileToUpload)            {                var curFile = Request.Files[file];              Stream sr=  curFile.InputStream;              byte[] filebyt = new byte[curFile.ContentLength];              Stream fileStream = curFile.InputStream;//建立文件流对象              fileStream.Read(filebyt, 0, curFile.ContentLength);                ServiceReference1.WebMp4serviceSoapClient sf = new ServiceReference1.WebMp4serviceSoapClient();               requesturl= sf.UpLoadStream(filebyt, curFile.FileName, "D:\\Video\\");                          }                      // ServiceReference1.WebMp4serviceSoapClient sf = new ServiceReference1.WebMp4serviceSoapClient();            //sf.u            return requesturl;        }

其次：webservice代码：

 [WebMethod]        public string UpLoadStream(byte[] fs, string fileName, string requestPath)        {            try            {                string oldName = System.IO.Path.GetFileName(fileName);                string expendName = System.IO.Path.GetExtension(oldName);                string newName = DateTime.Now.ToString().Replace(" ", "").Replace(":", "").Replace("-", "").Replace("/", "");                ///定义并实例化一个内存流，以存放提交上来的字节数组                ///                MemoryStream m = new MemoryStream(fs);                ///定义实际文件对象，保存上载的文件。                FileStream f = new FileStream(requestPath + newName + expendName, FileMode.Create);                                ///把内内存里的数据写入物理文件                m.WriteTo(f);                m.Close();                f.Close();                f = null;                m = null;                return requestPath + newName + expendName;            }            catch (Exception error) { }            return "";        }

返回上传文件URL用于保存到数据库（根据你自己的需求来改）

html代码

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<form id="form1" action="/VideoAdmin/UploadVide" method="post" enctype="multipart/form-data">
                    <table cellspacing="0" cellpadding="0" border="0" class="tableadd">
                        <tr>
                            <td>
                                选择视频：
                            </td>
                            <td>
                                <input id="btnfile" type="file" name="file"><input id="txturl" type="text" name="txturl"
                                    value="D:" /><input id="uploatvoide" type="submit" value="上传视频" />
                            </td>
                        </tr>
                        <tr>
                            <td>
                                视频名称
                            </td>
                            <td>
                                <input id="testvideoname" type="text" readonly="readonly" value="dddsds" />
                            </td>
                        </tr>
                        
                    </table>
                    </form>

代码经过测试，是可以的，希望帮到大家，写得不好，还希望不要见笑！

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