CODEFORCES 535A 解题报告

本题仍为水题，只要按照英语中的数字命名法来就可以了，STL简化一下操作，把基本元素枚举出来就可以了。map1～10，20，30，…，90。映射为单词。之后拆分十位和个位，用连字符拼接即可。
以下是代码（可直接AC）：

#include <iostream>#include <string>#include <map>using std::cin;using std::cout;using std::map;using std::string;int main(){    int s;    map<int,string> word;    //直接枚举    word[0]="zero";     word[1]="one";     word[2]="two";     word[3]="three";     word[4]="four";    word[5]="five";     word[6]="six";     word[7]="seven";     word[8]="eight";     word[9]="nine";    word[10]="ten";    word[11]="eleven";     word[12]="twelve";     word[13]="thirteen";     word[14]="fourteen";    word[15]="fifteen";     word[16]="sixteen";     word[17]="seventeen";     word[18]="eighteen";     word[19]="nineteen";    word[20]="twenty";     word[30]="thirty";     word[40]="forty";     word[50]="fifty";     word[60]="sixty";     word[70]="seventy";     word[80]="eighty";     word[90]="ninety";    cin>>s;    if(s>=0&&s<=19||s%10==0)//0~9不拆，整十不拆        cout<<word[s];    else        cout<<word[s-s%10]<<'-'<<word[s%10];//拆分输出    return 0;}