PAT刷题第一天。。。

来源：互联网发布：环球易购 php 编辑：程序博客网时间：2024/05/16 04:41

刷题第一天，刷了11题，应该是最简单了，发现自己还好许多要学习的地方。。。

例如：

给定不超过6的正整数A，考虑从A开始的连续4个数字。请输出所有由它们组成的无重复数字的3位数。

#include<stdio.h>int main(){  int m,n,k,l;  scanf("%d",&m);  n=m+1;  k=n+1;  l=k+1;  printf("%d %d %d %d %d %d\n",m*100+n*10+k,m*100+n*10+l,m*100+k*10+n,m*100+k*10+l,m*100+l*10+n,m*100+l*10+k);  printf("%d %d %d %d %d %d\n",n*100+m*10+k,n*100+m*10+l,n*100+k*10+m,n*100+k*10+l,n*100+l*10+m,n*100+l*10+k);  printf("%d %d %d %d %d %d\n",k*100+m*10+n,k*100+m*10+l,k*100+n*10+m,k*100+n*10+l,k*100+l*10+m,k*100+l*10+n);  printf("%d %d %d %d %d %d\n",l*100+m*10+n,l*100+m*10+k,l*100+n*10+m,l*100+n*10+k,l*100+k*10+m,l*100+k*10+n);  return 0;写成这样心也是蛮累的，眼睛花。。。

贴个别人写的，学习一下~

#include<stdio.h>int main(){   int a;   scanf("%d",&a);   int m[4] ;    int count = 0;   int i,j,k;   for(i=0;i<4;i++){
     m[i] = a+i;        }        for(i=0;i<4;i++){                for(j=0;j<4;j++){                        for(k=0;k<4;k++){                                if(k!=i&&k!=j&&i!=j){                                        printf("%d",m[i]*100+m[j]*10+m[k]);                                        count++;                                        if(count % 6 == 0){                                                printf("\n");                                        }else{                                                printf(" ");                                        }                                }                        }                }        }
  return 0;}

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