ZOJ Problem Set - 3869||Ace of Aces
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There is a mysterious organization called Time-Space Administrative Bureau (TSAB) in the deep universe that we humans have not discovered yet. This year, the TSAB decided to elect an outstanding member from its elite troops. The elected guy will be honored with the title of "Ace of Aces".
After voting, the TSAB received N valid tickets. On each ticket, there is a number Ai denoting the ID of a candidate. The candidate with the most tickets nominated will be elected as the "Ace of Aces". If there are two or more candidates have the same number of nominations, no one will win.
Please write program to help TSAB determine who will be the "Ace of Aces".
Input
There are multiple test cases. The first line of input contains an integer Tindicating the number of test cases. For each test case:
The first line contains an integer N (1 <= N <= 1000). The next line contains N integers Ai (1 <= Ai <= 1000).
Output
For each test case, output the ID of the candidate who will be honored with "Ace of Aces". If no one win the election, output "Nobody" (without quotes) instead.
Sample Input
352 2 2 1 151 1 2 2 31998
Sample Output
2Nobody998
浙江省第十二届大学生程序竞赛水题。
就是求输入的数字出现最多次数的那个数,如果有两个数同时多就输出Nobody。
#include <iostream>using namespace std;int main(){int t;cin >> t;while (t--){int n, i, j,a[1005] = { 0 }, x,max=0,mid=0,d;cin >> n;for (i = 0; i < n; i++){cin >> x;a[x]++;}for (i = 0; i < 1000; i++){if (a[i]>=max){mid = max;max = a[i];d = i;}}if (max == mid)cout << "Nobody" << endl;elsecout << d<<endl;}return 0;}
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