Merge Two Sorted Lists
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Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
题目的意思是给定两个有序链表,归并两个链表,并返回一个新的单链表
注意当两个链表中的数字有相等的时候,新的链表中是有重复的数字的。并且要注意头结点的建立,先建立一个头结点,最后返回的时候只是头结点的next
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */public class Solution { public ListNode mergeTwoLists(ListNode l1, ListNode l2) { if(l1==null&&l2==null) return null; ListNode result=new ListNode(-1); ListNode p=result; while(l1!=null&&l2!=null) { if(l1.val<l2.val) { ListNode node=new ListNode(l1.val); p.next=node; l1=l1.next; } else if(l1.val==l2.val) { ListNode node=new ListNode(l1.val); p.next=node; p=p.next; ListNode node2=new ListNode(l2.val); p.next=node2; l1=l1.next; l2=l2.next; } else{ ListNode node=new ListNode(l2.val); p.next=node; l2=l2.next; } p=p.next; } if(l1!=null) p.next=l1; if(l2!=null) p.next=l2; return result.next; }}
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