HDOJ 5222 Exploration
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题意:一个迷宫中,有n条无向隧道和m条有向隧道,每条隧道走过之后就会坍塌,不能再走,求是否存在从某一点出发能回到原点的情况。
链接:http://acm.hdu.edu.cn/showproblem.php?pid=5222
思路:对于无向图部分,通过并查集进行缩点,用缩点后的图进行有向图的判环(拓扑/强联通)
注意点:无
以下为AC代码:
Run IDSubmit TimeJudge StatusPro.IDExe.TimeExe.MemoryCode Len.LanguageAuthor136256212015-05-04 22:39:38Accepted52228470MS22208K4811 BC++luminous11/* ************************************************# @Author : Luminous11 (573728051@qq.com)*# @Date : 2015-05-02 15:32:28*# @Link : http://blog.csdn.net/luminous11*********************************************** */#include <algorithm>#include <iostream>#include <climits>#include <iomanip>#include <cstdlib>#include <cstring>#include <cctype>#include <cstdio>#include <string>#include <vector>#include <queue>#include <stack>#include <cmath>#include <ctime>#include <deque>#include <list>#include <map>#include <set>//#include <unordered_map>//#include <unordered_set>#define pb push_back#define ll long long#define ull unsigned long long#define all(x) (x).begin(), (x).end()#define READ(f) freopen(f, "r", stdin)#define WRITE(f) freopen(f, "w", stdout)#define clr(a, v) memset( a , v , sizeof(a) )#define RS(s) scanf ( "%s", s )#define RDI(a) scanf ( "%d", &a )#define RDII(a, b) scanf ( "%d%d", &a, &b )#define RDIII(a, b, c) scanf ( "%d%d%d", &a, &b, &c )#define PL() printf ( "\n" )#define PI(a) printf ( "%d", a )#define PIL(a) printf ( "%d\n", a )#define PSL(s) printf ( "%s\n", s )#define PII(a,b) printf ( "%d %d", a, b )#define PIIL(a,b) printf ( "%d %d\n", a, b )#define PIII(a,b,c) printf ( "%d %d %d", a, b, c )#define PIIIL(a,b,c) printf ( "%d %d %d\n", a, b, c )#define rep(i,m,n) for ( int i = m; i < n; i ++ )#define REP(i,m,n) for ( int i = m; i <= n; i ++ )#define dep(i,m,n) for ( int i = m; i > n; i -- )#define DEP(i,m,n) for ( int i = m; i >= n; i -- )#define repi(i,m,n,k) for ( int i = m; i < n; i += k )#define REPI(i,m,n,k) for ( int i = m; i <= n; i += k )#define depi(i,m,n,k) for ( int i = m; i > n; i += k )#define DEPI(i,m,n,k) for ( int i = m; i >= n; i -= k )#pragma comment ( linker, "/STACK:1024000000,1024000000" )using namespace std;template <class T>inline bool RD ( T &ret ){ char c; int sgn; if ( c = getchar(), c ==EOF )return 0; //EOF while ( c != '-' && ( c < '0' || c > '9' ) ) c = getchar(); sgn = ( c == '-' ) ? -1 : 1; ret = ( c == '-' ) ? 0 : ( c - '0' ); while ( c = getchar() , c >= '0' && c <= '9' ) ret = ret * 10 + ( c - '0' ); ret *= sgn; return 1;}inline void PD ( int x ){ if ( x > 9 ) PD ( x / 10 ); putchar ( x % 10 + '0' );}const double eps = 1e-10;const double pi = acos(-1.0);const int dir[4][2] = { 1,0, -1,0, 0,1, 0,-1 };struct node{ int x, y, cnt; node(){} node( int _x, int _y ) : x(_x), y(_y) {} node( int _x, int _y, int _cnt ) : x(_x), y(_y), cnt(_cnt) {}};struct edge{ int next, to; edge(){}};edge g[1000005];int head[1000005];int fa[1000005];int id[1000005];int tot;bool flag = 0;int point;int n, m1, m2;void init(){ tot = 0; flag = 0; point = 0; memset ( id, 0, sizeof ( id ) ); memset ( head, -1, sizeof ( head ) ); for ( int i = 0; i < 1000005; i ++ )fa[i] = i;}int find ( int x ){ if ( x == fa[x] ){ return x; } else{ fa[x] = find ( fa[x] ); return fa[x]; }}void merge ( int u, int v ){ int x = find ( u ); int y = find ( v ); if ( x == y ){ flag = 1; return; } else{ fa[x] = y; return; }}void addedge ( int u, int v ){ g[tot].next = head[u]; g[tot].to = v; head[u] = tot ++;}void topo(){ int be; vector<int> q; for ( int i = 1; i <= n; i ++ ){ if ( id[i] == 0 ){ q.push_back ( i ); } } for ( int i = 0; i < q.size(); i ++ ){ int be = q[i]; for ( int j = head[be]; j != -1; j = g[j].next ){ id[g[j].to] --; if ( id[g[j].to] == 0 ) q.push_back ( g[j].to ); } } int ans = q.size(); if ( ans != n )flag = 1; return;}int main(){ int T; scanf ( "%d", &T ); while ( T -- ){ init(); scanf ( "%d%d%d", &n, &m1, &m2 ); int u, v; for ( int i = 0; i < m1; i ++ ){ RD ( u ); RD ( v );//scanf ( "%d%d", &u, &v ); if ( flag )continue; merge ( u, v ); } for ( int i = 0; i < m2; i ++ ){ RD ( u );RD ( v );//scanf ( "%d%d", &u, &v ); if ( flag )continue; int x = find ( u ); int y = find ( v ); if ( x == y )flag = 1; addedge ( x, y ); id[y] ++; } if ( flag == 0 ){ topo(); } if ( flag ){ printf ( "YES\n" ); } else{ printf ( "NO\n" ); } } return 0;}
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