第九周项目一:复数类中的运算符重载(续)

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问题及代码:

在复数类中的运算符重载基础上
(1)再定义一目运算符 -,-c相当于0-c。
(2)定义Complex类中的<<和>>运算符的重载,实现输入和输出,改造原程序中对运算结果显示方式,使程序读起来更自然。

解决代码:

#include <iostream>using namespace std;class Complex{public:    Complex(){real=0;imag=0;}    Complex(double r,double i){real=r; imag=i;}    Complex operator+(const Complex &c2);    Complex operator-(const Complex &c2);    Complex operator*(const Complex &c2);    Complex operator/(const Complex &c2);    Complex operator-();    friend ostream& operator << (ostream&,const Complex&);    friend istream& operator >> (istream&,Complex&);private:    double real;    double imag;};//下面定义成员函数//复数相加: (a+bi)+(c+di)=(a+c)+(b+d)i.ostream& operator << (ostream& output,const Complex& c){    output<<"("<<c.real<<","<<c.imag<<"i)";    return output;}istream& operator >> (istream& input,Complex& c){    cout<<"please input real part and imaginary part:";    input>>c.real>>c.imag;    return input;}Complex Complex::operator+(const Complex &c2){    Complex c;    c.real=real+c2.real;    c.imag=imag+c2.imag;    return c;}//复数相减:(a+bi)-(c+di)=(a-c)+(b-d)i.Complex Complex::operator-(const Complex &c2){    Complex c;    c.real=real-c2.real;    c.imag=imag-c2.imag;    return c;}//复数相乘:(a+bi)(c+di)=(ac-bd)+(bc+ad)i.Complex Complex::operator*(const Complex &c2){    Complex c;    c.real=real*c2.real-imag*c2.imag;    c.imag=imag*c2.real+real*c2.imag;    return c;}//复数相除:(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)iComplex Complex::operator/(const Complex &c2){    Complex c;    c.real=(real*c2.real+imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);    c.imag=(imag*c2.real-real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);    return c;}int main(){    Complex c1,c2,c3;    cin>>c1>>c2;    cout<<"c1="<<c1<<endl;    cout<<"c2="<<c2<<endl;    c3=c1+c2;    cout<<"c1+c2="<<c3<<endl;    c3=c1-c2;    cout<<"c1-c2="<<c3<<endl;    c3=c1*c2;    cout<<"c1*c2="<<c3<<endl;    c3=c1/c2;    cout<<"c1/c2="<<c3<<endl;    return 0;}

运行结果:

学习心得:运用到了重载单目运算符,还有流插入运算符和流提取运算符,感觉重载了流插入运算符和流提取运算符后程序更加简明清晰了!


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