复数类中的运算符重载(续)
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代码:
#include <iostream>using namespace std;class Complex{public: Complex() { real=0; imag=0; } Complex(double r,double i) { real=r; imag=i; } Complex operator-(); friend ostream& operator << (ostream& output, const Complex& c); friend istream& operator >> (istream& input, Complex& c); friend Complex operator+(Complex &c1, Complex &c2); friend Complex operator+(double d1, Complex &c2); friend Complex operator+(Complex &c1, double d2); friend Complex operator-(Complex &c1, Complex &c2); friend Complex operator-(double d1, Complex &c2); friend Complex operator-(Complex &c1, double d2); friend Complex operator*(Complex &c1, Complex &c2); friend Complex operator*(double d1, Complex &c2); friend Complex operator*(Complex &c1, double d2); friend Complex operator/(Complex &c1, Complex &c2); friend Complex operator/(double d1, Complex &c2); friend Complex operator/(Complex &c1, double d2);private: double real; double imag;};ostream& operator << (ostream& output, const Complex& c){ output<<"("<<c.real; if(c.imag>=0) output<<"+"; output<<c.imag<<"i)"; return output;}istream& operator >> (istream& input, Complex& c){ int a,b; char sign,i; do { cout<<"input a complex number(a+bi或a-bi):"; input>>a>>sign>>b>>i; } while(!((sign=='+'||sign=='-')&&i=='i')); c.real=a; c.imag=(sign=='+')?b:-b; return input;}Complex Complex::operator-(){ return(0-*this);}//复数相加:(a+bi)+(c+di)=(a+c)+(b+d)i.Complex operator+(Complex &c1, Complex &c2){ Complex c; c.real=c1.real+c2.real; c.imag=c1.imag+c2.imag; return c;}Complex operator+(double d1, Complex &c2){ Complex c(d1,0); return c+c2; //按运算法则计算的确可以,但充分利用已经定义好的代码,既省人力,也避免引入新的错误,但可能机器的效率会不佳}Complex operator+(Complex &c1, double d2){ Complex c(d2,0); return c1+c;}//复数相减:(a+bi)-(c+di)=(a-c)+(b-d)i.Complex operator-(Complex &c1, Complex &c2){ Complex c; c.real=c1.real-c2.real; c.imag=c1.imag-c2.imag; return c;}Complex operator-(double d1, Complex &c2){ Complex c(d1,0); return c-c2;}Complex operator-(Complex &c1, double d2){ Complex c(d2,0); return c1-c;}//复数相乘:(a+bi)(c+di)=(ac-bd)+(bc+ad)i.Complex operator*(Complex &c1, Complex &c2){ Complex c; c.real=c1.real*c2.real-c1.imag*c2.imag; c.imag=c1.imag*c2.real+c1.real*c2.imag; return c;}Complex operator*(double d1, Complex &c2){ Complex c(d1,0); return c*c2;}Complex operator*(Complex &c1, double d2){ Complex c(d2,0); return c1*c;}//复数相除:(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)iComplex operator/(Complex &c1, Complex &c2){ Complex c; c.real=(c1.real*c2.real+c1.imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag); c.imag=(c1.imag*c2.real-c1.real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag); return c;}Complex operator/(double d1, Complex &c2){ Complex c(d1,0); return c/c2;}Complex operator/(Complex &c1, double d2){ Complex c(d2,0); return c1/c;}int main(){ Complex c1,c2,c3; double d=11; cout<<"c1: "<<endl;; cin>>c1; cout<<"c2: "<<endl; cin>>c2; cout<<"c1="<<c1<<endl; cout<<"c2="<<c2<<endl; cout<<"d="<<d<<endl; //cout<<"-c1="<<(-c1); c3=c1+c2; cout<<"c1+c2="<<c3<<endl; cout<<"c1+d="<<(c1+d)<<endl; cout<<"d+c1="<<(d+c1)<<endl; c3=c1-c2; cout<<"c1-c2="<<c3<<endl; cout<<"c1-d="<<(c1-d)<<endl; cout<<"d-c1="<<(d-c1)<<endl; c3=c1*c2; cout<<"c1*c2="<<c3<<endl; cout<<"c1*d="<<(c1*d)<<endl; cout<<"d*c1="<<(d*c1)<<endl; c3=c1/c2; cout<<"c1/c2="<<c3<<endl; cout<<"c1/d="<<(c1/d)<<endl; cout<<"d/c1="<<(d/c1)<<endl; return 0;}
运行结果:
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