leetcode: Longest Valid Parentheses
来源：互联网 发布：illustrator mac 破解 编辑：程序博客网 时间：2024/04/29 10:39
没明白为啥要递减循环
http://www.tuicool.com/articles/vUnEbi
递增循环ac好好的
class Solution: # @param {string} s # @return {integer} def longestValidParentheses(self, s): if not s: return 0 maxlen = 0 n = len(s) dp = [0]*n #print dp for i in range(1,n): if s[i]==')': j = i-1 - dp[i-1] if j>=0 and s[j]=='(': dp[i] = dp[i-1]+2 #combine if j-1 >= 0: dp[i] += dp[j-1] if dp[i]>maxlen: maxlen = dp[i] #print 'dp[%d]=%d'%(i,dp[i]) #print dp return maxlen 0 0
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