Leetcode: Length of Last Word
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Question
Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = “Hello World”,
return 5.
Hide Tags String
Analysis
Solution
Mistake taken
- The first thought is use string.split(), and return s[-1]. However, there maybe multiple ” ” at the end of string.
Code
class Solution: # @param {string} s # @return {integer} def lengthOfLastWord(self, s): if s==" ": return 0 s = s.split(" ") for i in range(len(s)-1,-1,-1): if len(s[i])>0: return len(s[i]) return 0
0 0
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