Leetcode: Length of Last Word

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Question

Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = “Hello World”,
return 5.

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Analysis


Solution

Mistake taken

  1. The first thought is use string.split(), and return s[-1]. However, there maybe multiple ” ” at the end of string.

Code

class Solution:    # @param {string} s    # @return {integer}    def lengthOfLastWord(self, s):        if s==" ":            return 0        s = s.split(" ")        for i in range(len(s)-1,-1,-1):            if len(s[i])>0:                return len(s[i])        return 0
0 0
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