Leetcode 33 Search in Rotated Sorted Array
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class Solution: # @param {integer[]} nums # @param {integer} target # @return {integer} def search(self, nums, target): for i in xrange(len(nums)): if nums[i]==target: return i return -1二分法：
class Solution: # @param {integer[]} nums # @param {integer} target # @return {integer} def search(self, nums, target): left,right=0, len(nums)-1 while left <= right: mid=(left + right)/2 if nums[mid] == target: return mid if nums[left] <= nums[mid]: if nums[left] <= target < nums[mid]: right = mid-1 else: left = mid+1 else: if nums[mid] < target <= nums[right]: left = mid+1 else: right = mid-1 return -1 0 0
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