Multivariate Gaussian Distribution

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Multivariate Gaussian Distribution

Ethara

This work will present a linear transformation interpretation on the multivariate Gaussian distribution. The entire derivation is originated from univariate Gaussian distributions with mean 0 and variance 1.

Recall that the density function of a univariate Gaussian distribution is given by


Therefore, when


we have


Now, suppose we haven independently identically distribution random variables x1, …, xn conforming to univariate Gaussian distributions with mean 0 and variance 1, then the joint density function is


By designing a vector-valued random variable,


we can re-write the joint density function as


Remarkably, here is the assumption that will lead us to a general case, that is, there exists an invertible mixing matrix and a noise vector mu which contributes to a linear transformation from to X, i.e.,


Problem is, what is density function of X? Here is the derivation. (This requires some advanced linear algebra and probability theory. The relevant proof is on the horizon.)


Letting


we can obtain


where the noise vector muis the mean of X, since E[X] = E[BZ] + E[mu] = mu, and the n-by-n matrix SIGMA is a symmetric positive semi-definite covariance matrix of X, since



Moreover, since SIGMA is real symmetric, it can be factorized as


where U is a full rank orthogonal matrix containing the eigenvectors of SIGMA as its columns and LAMBDA is a diagonal matrix containing SIGMA’s eigenvalues which are non-negative. (Since SIGMA is also positive semi-definite)

Defining


to be the diagonal matrix whose entries are the square roots of the corresponding entries from LAMBDA. Noting that


we have


Therefore, the mixing matrix turns out to be


In addition, by inversing the derivation above, we can substantiate the probabilistic standardization of multivariate Gaussian distribution, i.e.,


Proof sketch:

Noting that,


where C is nonsingular, we have,


Substitute CT(X-mu) for Y,


where


we obtain,


Incidentally, the Jacobian determinant plays an essential part in multivariate integral by substitution, geometrically suggesting the value of volume element of an n-dimensional stretched cube composed of a new basis into which the old one is linearly or nonlinearly transformed in Euclidean space.

POSTSCRIPT

Happy birthday to my dear bro, Ryan! Hopefully, one day, you will become an extraordinary mathematician like Johann Carl Friedrich Gauss.

MAY 24th, 2015


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