12期算法擂台解答

 

时间表达

英文口语表达时间有如下6种句型：

l         It is five past seven.（7点5分）

l         It is eleven to ten. （9点49分）

l         It is half past nine. （9点30分）

l         It is a quarter past eight. （8点15分）

l         It is a quarter to ten. （9点45分）

l         It is three o’clock. （3点）

请根据输入的时间，输出相应的英文表达。

程序从键盘输入多行数据，每一行为两个非负整数A和B，其中0<=A<13，0<=B<60，分别表示小时数和分钟数。如果输入的某一行为0 0，则表示输入已结束。程序输出要求：对于输入的每一行（最后的0 0行除外），输出相应的时间表达字符串，要求为上面6种句型之一。输入输出样例见下:

 

样例输入

8 21

12 45

5 0

0 30

0 0

样例输出

It is twenty-one past eight.

It is a quarter to thirteen.

It is five o’clock.

It is half past zero.

#include <iostream>
        #include <string>
        using namespace std;

int main()
{
 int hour, minute;  // 小时数和分钟数
 const string STR[] = {"zero", "one",  "two",  "three", "four",  "five",  "six", "seven",
        "eight", "nine",  "ten",  "eleven", "twelve", "thirteen","fourteen",
        "a quarter", "sixteen", "seventeen", "eighteen", "nineteen", "twenty",
        "twenty-one", "twenty-two", "twenty-three", "twenty-four", "twenty-five",
        "twenty-six", "twenty-seven", "twenty-eight", "twenty-nine", "half"};
 while (cin >> hour >> minute)
 {
  if (hour == 0 && minute == 0) // 0 0行，退出
   break;
  if (minute == 0) // 整点
   cout << "It is " << STR[hour] << " o'clock." << endl;
  else if (minute <= 30) // 不超过30分
   cout << "It is " << STR[minute] << " past " << STR[hour] << "." << endl;
  else // 超过30分
   cout << "It is " << STR[60 - minute] << " to " << STR[hour + 1] << "." << endl;
 }
 return 0;
}