ACM-I'll play a trick on you
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- 描述
- Please look the picture carefully. Then I'll give you two integers and your task is output the third one.
Please never doubt the picture.- 输入
- The first line is a number T(1<=T<=30), represents the number of case. The next T blocks follow each indicates a case.
Each case contains two integers A,B (1<=B<=A<=10^100) - 输出
- For each case, output the number of case and the third integer.
- 样例输入
399 7245 2739 18
- 样例输出
271821
代码:
01.
#include<iostream>
02.
#include<string>
03.
using
namespace
std;
04.
int
main()
05.
{
06.
int
t;
07.
cin>>t;
08.
while
(t--)
09.
{
10.
string a,b;
11.
int
i,sum=0;
12.
cin>>a>>b;
13.
for
(i =0;i <a.length();i++)
14.
sum += a[i] -
'0'
;
15.
for
(i = 0;i < b.length();i++)
16.
sum += b[i] -
'0'
;
17.
cout<<sum<<endl;
18.
}
19.
return
0;
20.
}
0 0
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