poj 1064

二分题，不解释#include<iostream>#include<cstdlib>#include<cstdio>#include<cmath>using namespace std; int   n,m;double a[10005];int solve(double x){int i,j;int  sum=0;for(i=0;i<n;i++){sum+=int(a[i]/x);}return sum;}int main(){cin>>n>>m;int   i,j;for(i=0;i<n;i++){cin>>a[i];}double l=0;double r = 100000;double  mid;int   ans;for(i=0;i<1000;i++){mid=(l+r)/2;ans=solve(mid);if(ans>=m){l=mid;}else{r=mid;}}printf("%.2f\n",floor(l*100)/100);}