LeetCode -- Add Two Numbers

Add Two Numbers

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8

/** * Definition for singly-linked list. * struct ListNode { *     int val; *     ListNode *next; *     ListNode(int x) : val(x), next(NULL) {} * }; */class Solution {public:    ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {            ListNode *newNode = new ListNode(0);            ListNode *resultNode = newNode;            int carry = 0;            while(l1!=NULL||l2!=NULL){                int v = 0;                if(l1!=NULL){                    v = l1->val;                    l1 = l1->next;                }                if(l2!=NULL){                    v +=l2->val;                    l2 = l2->next;                }                resultNode->next = new ListNode((v+carry)%10);                carry = (v+carry)/10;                resultNode = resultNode->next;            }            if(carry>0){                resultNode->next = new ListNode(1);            }            return newNode->next;        }};