LeetCode 199. Binary Tree Right Side View
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BFS, 注意要先对右节点调用BFS即可。
代码:
class Solution {public: vector<int> rightSideView(TreeNode *root) { bfs(root, 1); return ret; }private:void bfs(TreeNode* node, int level){if (node == nullptr){return ;}if (ret.size() < level){ret.push_back(node->val);}bfs(node->right, level+1);bfs(node->left, level+1);}vector<int> ret;};
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