hdu 1170 Balloon Comes

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Balloon Comes!

气球来了！

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 22727 Accepted Submission(s): 8577

Problem Description

The contest starts now! How excited it is to see balloons floating around. You, one of the best programmers in HDU,

现在比赛开始！气球升起激动的时刻来了。你作为HDU优秀的编程员之一。

can get a very beautiful balloon if only you have solved the very very very... easy problem.

如果能解决这个非常非常非常难的问题，那么你就可以得到一个美丽的气球。
Give you an operator (+,-,*, / --denoting addition, subtraction, multiplication, division respectively)

你（respectively分别）能用，（addition加），（subtraction减），（multiplication乘），（division除），（denoting 指示）

and two positive integers, your task is to output the result.

两个整正数，你的任务是输出他们的结果。
Is it very easy?

很简单吧？
Come on, guy! PLMM will send you a beautiful Balloon right now!

小子，来吧！漂亮美眉会立刻给你一个么美丽的气球！
Good Luck!

祝你好运！

Input

Input contains multiple test cases. The first line of the input is a single integer T (0<T<1000) which is the number of test cases.

输入包含多个测试用例。输入的第一行是T,T指的是有多少个测试用例。

T test cases follow. Each test case contains a char C (+,-,*, /) and two integers A and B(0<A,B<10000).

然后T行。每一行包含一个字符和两个数字，字符为（ + - * / ），A ， B(0<A,B<10000)。

Of course, we all know that A and B are operands and C is an operator.

当然，A C B = D,也就是C是运算符，D是A与B运算的答案。

Output

For each case, print the operation result. The result should be rounded to 2 decimal places If and only if it is not an integer.

对于每一个测试用例，输出结果。（小数***）结果应四舍五入小数点后2位（当且仅当它不是一个整数------注意：如果结果不是小数就不要精确）。

Sample Input

4+ 1 2- 1 2* 1 2/ 1 2

Sample Output

3-120.50

这题没压力啊！！

import java.util.Scanner;public class Main {public static void main(String[] args) {Scanner sc = new Scanner(System.in);int t = sc.nextInt();while (t-- > 0) {String str = sc.next();int a = sc.nextInt();int b = sc.nextInt();switch (str.charAt(0)) {case '+':str = "" + (a + b);break;case '-':str = "" + (a - b);break;case '*':str = "" + (a * b);break;case '/':if (a / b * b == a) {str = "" + (a / b);} else {str = String.format("%.2f", 1.0 * a / b);}break;default:break;}System.out.println(str);}}}

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