servlet后台如何接收对象参数

来源：互联网发布：域名查询美橙互联编辑：程序博客网时间：2024/05/21 13:21

主要思想是用js把对象转换成json，然后把json提交到后台去，后台把这个json字符串转换成map对象

<script type="text/javascript">function do_test(){var req = {};req['id'] = 1;req['name'] = '项羽';req['dynasty'] = '楚国';var info = {};info['nick'] = '西楚霸王';info['age'] = 47;var user1 = {};user1['userid'] = 100;user1['username'] = '英布';user1['position'] = '九江王';var user2 = {};user2['userid'] = 200;user2['username'] = '魏豹';user2['position'] = '西魏王';var user3 = {};user3['userid'] = 300;user3['username'] = '张耳';user3['position'] = '常山王';var list = [user1, user2, user3];req['info'] = info;req['list'] = list;var json = JSON.stringify(req);$.post('/leshop/home.do', {'reqInfos': json}, function(res){console.log(res);});}</script>

后台servlet端，直接用request.getParameter("reqInfos")，然后转换成对象

如Map<String, Object> map = g.fromJson(req.getParameter("reqInfos"), Map.class);

然后遍历这个对象即可

map.get("list") 是ArrayList对象，这个ArrayList里面是Map

7 0