morley's theorem uva11178
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1、问题描述
2、只用利用直线交点求解即可,注意三分线可以用Rotate函数更新
#include <iostream>#include<cmath>using namespace std;/* run this program using the console pauser or add your own getch, system("pause") or input loop */struct point{ double x,y; point(double x=0,double y=0):x(x),y(y){}};typedef point Vector;Vector operator+(Vector a,Vector b){ return Vector(a.x+b.x,a.y+b.y);}Vector operator-(Vector a,Vector b){ return Vector(a.x-b.x,a.y-b.y);}Vector operator*(Vector a,double p){ return Vector(a.x*p,a.y*p);}Vector operator/(Vector a,double p){ return Vector(a.x/p,a.y/p);}bool operator <(const point&a,const point&b){ return a.x<b.x||(a.x==b.x&&a.y<b.y);}const double eps=1e-10;int dcmp(double x){ if(fabs(x)<eps)return 0; else return x<0?-1:1;}bool operator ==(const point&a,const point&b){ return dcmp(a.x-b.x)==0&&dcmp(a.y-b.y)==0;}double Dot(Vector a,Vector b){ return a.x*b.x+a.y*b.y;}double Length(Vector a){ return sqrt(Dot(a,a));}double Angle(Vector a,Vector b){ return acos(Dot(a,b)/Length(a)/Length(b));}double Cross(Vector a,Vector b){ return a.x*b.y-a.y-b.x;}double Area2(point a,point b,point c){ return Cross(b-a,c-a);}Vector Rotate(Vector a,double rad){ return Vector(a.x*cos(rad)-a.y*sin(rad),a.x*sin(rad)+a.y*cos(rad));}point Getlineintersection(point p,Vector v,point q,Vector w){//两条直线交点 Vector u=p-q; double t=Cross(w,u)/Cross(v,w); return p+v*t;}double distancetoline(point p,point a,point b){ Vector v1=b-a,v2=p-a; return fabs(Cross(v1,v2))/Length(v1);}point getd(point a,point b,point c){ Vector v1=c-b; double a1=Angle(a-b,v1); v1=Rotate(v1,a1/3); Vector v2=b-c; double a2=Angle(a-c,v2); v2=Rotate(v2,-a2/3); return Getlineintersection(b,v1,c,v2);}point read_point(){ int x,y; cin>>x>>y; point a(x,y); return a;}int main(int argc, char** argv) { int t; point a,b,c,d,e,f; cin>>t; while(t--){ a=read_point(); b=read_point(); c=read_point(); d=getd(a,b,c); e=getd(b,c,a); f=getd(c,a,b); cout<<endl; } return 0;}
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