数制转换问题：skew

//poj:2973#include<stdio.h>#include<string.h>int main(){int i,k,base[31];char skew[32];base[0]=1;for(i=1;i<32;i++)base[i]=2*base[i-1]+1;while(1){scanf("%s",skew);if(strcmp(skew,"0")==0)break;k=strlen(skew);int sum=0;for(i=0;i<strlen(skew);i++){k--;sum+=(skew[i]-'0')*base[k];}printf("%d\n",sum);}return 0;}