IP Address

IP Address

Time Limit: 1000MS Memory Limit: 30000KTotal Submissions: 19125 Accepted: 11053

Description

Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are:

27   26  25  24  23   22  21  20 128 64  32  16  8   4   2   1 

Input

The input will have a number N (1<=N<=9) in its first line representing the number of streams to convert. N lines will follow.

Output

The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.

Sample Input

400000000000000000000000000000000 00000011100000001111111111111111 11001011100001001110010110000000 01010000000100000000000000000001 

Sample Output

0.0.0.03.128.255.255203.132.229.12880.16.0.1

二进制转化

#include <cstdio>#include <string.h>#include <cmath>#include <iostream>#include <algorithm>#define WW freopen("output.txt","w",stdout)using namespace std;int main(){    char s[100];    int T;    scanf("%d",&T);    while(T--)    {        scanf("%s",s);        int len=strlen(s);        int a[5];        int sum=0,ans=1;        for(int j=1,i=len-1;i>=0;i--,j++)        {            if(j%8)            {                sum=(s[i]-'0')*ans+sum;                ans*=2;            }            else            {                 sum=(s[i]-'0')*ans+sum;                 ans=1;                 a[j/8]=sum;                 sum=0;            }        }        printf("%d.%d.%d.%d\n",a[4],a[3],a[2],a[1]);    }    return 0;}