1019. General Palindromic Number (20):郁闷了,深呼吸,做道题···
来源:互联网 发布:华三基于端口nat配置 编辑:程序博客网 时间:2024/04/29 06:31
注意 边界条件 当N==0时
#include<iostream>#include<vector>using namespace std;int main(){ int N, b; vector<int>V; while( cin>>N>>b ) { V.clear(); do { V.push_back(N%b); N/=b; }while(N!=0); int len = V.size(); bool flag=false; for(int j=0; j<len; j++ ) if( V[j]!=V[len-1-j] ) { cout<<"No"<<endl; flag = true; break; } if( !flag ) cout<<"Yes"<<endl; cout<<V[len-1]; for( int j=len-2; j>=0; j-- ) cout<<" "<<V[j]; cout<<endl; } return 0;}
0 0
- 1019. General Palindromic Number (20):郁闷了,深呼吸,做道题···
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
- 1019. General Palindromic Number (20)
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- 1019. General Palindromic Number (20):郁闷了,深呼吸,做道题···
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