字符串补位

来源：互联网发布：淘宝网迪奥香水编辑：程序博客网时间：2024/04/30 06:02

分析：现有字符串"a",转换byte后假设取位为:00110001,现去掉第一个0为0110001,补位加0为01100010.

现要求将一组去掉第一位的串将第一位重新添加回来，即分析的逆过程。代码如下

byte [] aryBytes = temp.getBytes();StringBuffer sbtmp = new StringBuffer();StringBuffer sb = new StringBuffer();System.out.println("content内容:"+temp);for(int i=0;i<aryBytes.length;i++){sbtmp.append((byte)((aryBytes[i] >> 7) & 0x1));sbtmp.append((byte)((aryBytes[i] >> 6) & 0x1));sbtmp.append((byte)((aryBytes[i] >> 5) & 0x1));sbtmp.append((byte)((aryBytes[i] >> 4) & 0x1));sbtmp.append((byte)((aryBytes[i] >> 3) & 0x1));sbtmp.append((byte)((aryBytes[i] >> 2) & 0x1));sbtmp.append((byte)((aryBytes[i] >> 1) & 0x1));sbtmp.append((byte)((aryBytes[i] >> 0) & 0x1));}System.out.println("原始二进制串:"+sbtmp);int length = sbtmp.length();for(int i=0;i<length/7;i++){sb.append("0"+sbtmp.substring(i*7,(i+1)*7));}System.out.println("补0后二进制串:"+sb);byte [] bytes = new byte[sb.length()/8];for(int i=0;i<sb.length()/8;i++){bytes[i] = Byte.parseByte(sb.substring(i*8, (i+1)*8),2);}new String(bytes);

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