WERTYU(UVa 10082)

Problem Description
WERTYU
A common typing error is to place the hands on the keyboard one row to the right of the correct position. So “Q” is typed as “W” and “J” is typed as “K” and so on. You are to decode a message typed in this manner.

Input
Input consists of several lines of text. Each line may contain digits, spaces, upper case letters (except Q, A, Z), or punctuation shown above [except back-quote (`)]. Keys labelled with words [Tab, BackSp, Control, etc.] are not represented in the input.

Output
You are to replace each letter or punctuation symbol by the one immediately to its left on the QWERTY keyboard shown above. Spaces in the input should be echoed in the output.

Sample Input
O S, GOMR YPFSU/

Sample Output
I AM FINE TODAY.

#include <stdio.h>char s[] = "`1234567890-=qwertyuiop[]\\asdfghjkl;'zxcvbnm,./";int main(){    int i, c;    while((c = getchar()) != EOF){        for(i = 1; s[i] && s[i] != c; i++);            if(s[i])                putchar(s[i-1]);            else                 putchar(c);    }    return 0;}

注：

1. 使用常量数组，i-1位置上的字符必定是i位置字符对应的正确字符。
2. for循环后面是一个空语句，这个循环的目的是找到c对应的s[i]，如果存在，输出s[i-1]，不存在，输出本来的字符。