Uva - 120 - Stacks of Flapjacks
来源:互联网 发布:7u分享网络可信吗 编辑:程序博客网 时间:2024/05/16 17:44
选择排序,从大到小顺序一次排列,每次先把第 i 大的翻到最上面,然后在翻到正确的位置。
AC代码:
#include <iostream>#include <cstdio>#include <cstdlib>#include <cctype>#include <cstring>#include <string>#include <sstream>#include <vector>#include <set>#include <map>#include <algorithm>#include <stack>#include <queue>#include <bitset> #include <cassert> #include <cmath>using namespace std;const int maxn = 35;int n, pancakes[maxn];void filp(int p){for (int i = 0; i < p - i; i++) {swap(pancakes[i], pancakes[p - i]);}cout << n - p << " ";}int main(){ios::sync_with_stdio(false);string s;while (getline(cin, s)) { // 不知道一次有多少个,直接读取一行cout << s << endl;stringstream ss(s);n = 0;while (ss >> pancakes[n]) {n++;}for (int i = n - 1; i > 0; i--) {int maxP = max_element(pancakes, pancakes + i + 1) - pancakes;if (maxP == i) { // 如果最大元已经在最底部,不用翻转了continue;}if (maxP > 0) {filp(maxP); // 大最大元先翻到最上面}filp(i); // 然后翻到正确的位置}cout << "0\n";}return 0;}
0 0
- UVA 120 Stacks of Flapjacks
- UVa 120 - Stacks of Flapjacks
- uva 120 Stacks of Flapjacks
- UVA 120 - Stacks of Flapjacks
- uva 120 - Stacks of Flapjacks
- UVa 120 - Stacks of Flapjacks
- UVA 120 - Stacks of Flapjacks
- UVa 120 - Stacks of Flapjacks
- UVA 120Stacks of Flapjacks
- UVA 120 - Stacks of Flapjacks
- uva 120 Stacks of Flapjacks
- UVA 120 Stacks of Flapjacks
- uva 120 Stacks of Flapjacks
- uva - 120 - Stacks of Flapjacks
- UVa 120 - Stacks of Flapjacks
- UVA - 120 - Stacks of Flapjacks
- UVa:120 - Stacks of Flapjacks
- UVa 120 - Stacks of Flapjacks
- 剑指offer 面试题2
- POJ 1247 Magnificent Meatballs(水~)
- 拟把疏狂图一醉
- Web服务在本地PC的负载均衡(根据IP不同进行分配)
- C++线性代数库Armadillo
- Uva - 120 - Stacks of Flapjacks
- CodeForces 354A - Vasya and Robot (简单思维)
- 洗刷刷OO三A
- hypercall的实现机制与硬件虚拟化
- 深入理解Java对象序列化
- Android下用OpenCV3.0库静态链接错误解决方法
- lisp基本操作及其函数名解释
- list容器
- 第十六周【项目2-有些数的阶乘不算了】