Length of Last Word
来源:互联网 发布:mac口红哪款滋润度好 编辑:程序博客网 时间:2024/06/07 17:47
Given a string s consists of upper/lower-case alphabets and empty space characters' '
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
从后往前计算,先要除去后面的空格,遇到第一个不是空格开始计算,遇到空格停止。
class Solution {public: int lengthOfLastWord(string s) { int l=s.size(),count=0; while(s[l-1]==' ')l--; for(int i=l-1;i>=0;i--){ if(s[i]!=' ') count++; else break; } return count; }};
0 0
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- Length of Last Word
- 6.13
- Oracle启动服务详解
- 6.14
- Qt中的各种字符串转换问题
- 2015062705 - EffactiveJava笔记 - 第38条 检查参数的有效性
- Length of Last Word
- javascript的函数上下文this四条规则
- Ubuntu12.04 tftp服务安装与测试
- SSH框架整合(一) —— Spring与Struts2整合
- 解决 如何删除Android studio中创建的工程!
- 今天开始创建CSDN博客,谨以此记录。
- JAVA线程堆栈问题定位第一讲
- php
- win7 启动telnet服务