【Leetcode Algorithm】Min Stack

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Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.

  • push(x) -- Push element x onto stack.
  • pop() -- Removes the element on top of the stack.
  • top() -- Get the top element.
  • getMin() -- Retrieve the minimum element in the stack.
public class Solution {    public int[] plusOne(int[] digits) {        //从个位开始加1,如果产生进位直接置为0,没有进位则,跳出循环        for(int i=digits.length-1;i>=0;i--){            if((digits[i] += 1)==10){                digits[i] = 0;            }            else{                break;            }        }        //如果最高位为0,说明产生进位,则数组加长,首位为1        if(digits[0]==0){            int[] newDigits = new int[digits.length+1];            newDigits[0] = 1;            digits = newDigits;        }        return digits;    }}

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