org.apache.commons.fileupload实现文件上传

来源：互联网发布：nodejs 引入js文件编辑：程序博客网时间：2024/06/06 03:13

<context-param>    <param-name>FileUploadToServer</param-name>    <param-value>true</param-value>  </context-param>  <context-param>    <param-name>FileUploadLocalFolder</param-name>    <param-value>FILE_UPLOAD</param-value>  </context-param>

String referenceID = request.getParameter("referenceID");String toServer = application.getInitParameter("FileUploadToServer");if(toServer.equals("true")){ 　　　　String filePath = application.getRealPath("/")+application.getInitParameter("FileUploadLocalFolder");　　//建立文件工厂　　DiskFileItemFactory factory = new DiskFileItemFactory();　　//设置上传工厂的限制　　factory.setSizeThreshold(1024 * 1024 * 20);　　//创建一个上传文件的ServletFileUpload对象　　ServletFileUpload upload = new ServletFileUpload(factory);　　List items = upload.parseRequest(request);　　Iterator<FileItem> iter = list.iterator(); 　　while (iter.hasNext()) {　　　　FileItem item = iter.next();　　　　String filename = item.getName();//获取上传文件的名称　　　　File outfilepath = new File(filePath);//创建文件路径　　　　if(!outfilepath.isDirectory()){　　　　　　outfilepath.mkdir();　　　　}　　　　fileItem.write(new File(filePath + "\\" + referenceID + "\\" +filename));　　}}

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