UVa400 Unix ls

Description

The computer company you work for is introducing a brand new computer line and is developing a new Unix-like operating system to be introduced along with the new computer. Your assignment is to write the formatter for the ls function.

Your program will eventually read input from a pipe (although for now your program will read from the input file). Input to your program will consist of a list of (F) filenames that you will sort (ascending based on the ASCII character values) and format into (C) columns based on the length (L) of the longest filename. Filenames will be between 1 and 60 (inclusive) characters in length and will be formatted into left-justified columns. The rightmost column will be the width of the longest filename and all other columns will be the width of the longest filename plus 2. There will be as many columns as will fit in 60 characters. Your program should use as few rows (R) as possible with rows being filled to capacity from left to right.

Input

The input file will contain an indefinite number of lists of filenames. Each list will begin with a line containing a single integer (  ). There will then be N lines each containing one left-justified filename and the entire line's contents (between 1 and 60 characters) are considered to be part of the filename. Allowable characters are alphanumeric (a to z, A to Z, and 0 to 9) and from the following set { ._- } (not including the curly braces). There will be no illegal characters in any of the filenames and no line will be completely empty.

Immediately following the last filename will be the N for the next set or the end of file. You should read and format all sets in the input file.

Output

For each set of filenames you should print a line of exactly 60 dashes (-) followed by the formatted columns of filenames. The sorted filenames 1 to R will be listed down column 1; filenames R+1 to 2R listed down column 2; etc.

Sample Input

10tiny2short4mevery_long_file_nameshortersize-1size2size3much_longer_name12345678.123mid_size_name12WeaserAlfalfaStimeyBuckwheatPorkyJoeDarlaCottonButchFroggyMrs_CrabappleP.D.19Mr._FrenchJodyBuffySissyKeithDannyLoriChrisShirleyMarshaJanCindyCarolMikeGregPeterBobbyAliceRuben

Sample Output

------------------------------------------------------------12345678.123         size-1               2short4me            size2                mid_size_name        size3                much_longer_name     tiny                 shorter              very_long_file_name  ------------------------------------------------------------Alfalfa        Cotton         Joe            Porky          Buckwheat      Darla          Mrs_Crabapple  Stimey         Butch          Froggy         P.D.           Weaser         ------------------------------------------------------------Alice       Chris       Jan         Marsha      Ruben       Bobby       Cindy       Jody        Mike        Shirley     Buffy       Danny       Keith       Mr._French  Sissy       Carol       Greg        Lori        Peter

Unix中ls命令，可以查看目录下的文件，按字母顺序显式且自动打印成表格形式。

题目大概意思就是模拟这个过程，输入n，接着输入n个文件名，按ls命令那样输出。

找到目录中文件名最长的，每行的文件数量应该一致，最后一行除外，且每行最多包含60个字符。

以最长文件名长度确定列数，以列数计算行数，注意最后一行可能没有填满。

以列为顺序，按字母顺序输出。

#include <cstdio>#include <cstring>#include <iostream>#include <algorithm>using namespace std;int cmp(const void *a,const void *b){return strcmp((char *)a,(char *)b);}char str[110][100];int main(){//freopen("test.in","rt",stdin);int i,j,len,n,h,l,s;while(cin >>n){len = 0;for(i = 0;i < n;i++){cin >>str[i];if(strlen(str[i]) > len)len = strlen(str[i]);<span style="white-space:pre"></span>//确定最长的文件名}qsort(str,n,100*sizeof(char),cmp);cout <<"------------------------------------------------------------" <<endl;l = 62/(len+2);         //2为空格，计算出多少列h = (n%l)?n/l+1:n/l;        //计算多少行for(i = 0;i < h;i++){for(j = 0;j < l;j++){if(j*h+i >= n)      //输出每行后回车break;cout <<str[j*h+i];s = len - strlen(str[j*h+i]);   //计算当前单词与最长单词的长度差距，补足空格while(s--) cout <<" ";if(j != l-1)cout <<"  ";           //单词之间有两个空格间隔，也就是之前计算列数时的2}cout <<endl;}}return 0;}