codeforces 448 A. Rewards
来源:互联网 发布:万方数据库高级检索 编辑:程序博客网 时间:2024/05/16 07:13
题目链接:http://codeforces.com/contest/448/problem/A
提示:水,看懂题即可
#include <iostream>#include <cstdio>using namespace std;int main(){ int a[3]; int b[3]; int m; int suma=0,sumb=0; for(int i=0; i<3; i++) cin>>a[i],suma+=a[i]; for(int i=0; i<3; i++) cin>>b[i],sumb+=b[i]; cin>>m; if(suma%5==0) suma/=5; else suma=suma/5+1; if(sumb%10==0) sumb/=10; else sumb=sumb/10+1; //cout<<suma<<" "<<sumb<<endl; if(suma+sumb>m) puts("NO"); else puts("YES"); return 0;}
0 0
- codeforces-448A-Rewards
- Codeforces 448A Rewards
- CodeForces 448-A. Rewards
- CodeForces 448A Rewards
- codeforces 448 A. Rewards
- codeforces #256 A. Rewards
- codeforces—— 448A —— Rewards
- 448A - Rewards
- Codeforces Round #256 (Div. 2) A. Rewards
- Codeforces Div. 2 #256-A. Rewards
- Codeforces Round #256 (Div. 2) A. Rewards
- Codeforces Round #256 (Div. 2) A. Rewards
- A. Rewards
- Codeforces Round #256 (Div. 2) A. Rewards(简单题)
- Rewards - #256 (Div. 2) A (448A)水题
- CF (Round#256) A. Rewards
- CF#256(Div.2) A. Rewards
- Discover the Rewards of Owning A CNC Router
- 重新开始BAE
- 十年WEB技术发展历程
- Nodejs中when库的实例介绍
- 图像微分(1、2阶导数和拉普拉斯算子)
- Android5.0网络之多网络共存与应用
- codeforces 448 A. Rewards
- WIZnet相关产品介绍
- Xcode6 如何新建空模板
- android的parcelable接口
- ubuntu设置网卡速率
- Codeforces Round #288 (Div. 2) D. Tanya and Password 欧拉回路
- 生成序列
- hdu 2521
- 36.数组中的逆序对