五猴分桃问题

#include <stdio.h>void out(){    int n,sum,i=1;    for(n=1;n<=10000;n++)    {        sum=n;        for(i=1;i<=5;++i)            if((sum*5+1)%4!=0)                break;            else                sum=(sum*5+1)/4;        if(i==5)            break;    }    printf("%d\n",sum * 5 + 1);}int main(int argc, const char * argv[]){    out();        return 0;}