【LintCode】 Compare Strings 比较字符串

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比较两个字符串A和B，确定A中是否包含B中所有的字符。字符串A和B中的字符都是大写字母。

样例
给出 A = “ABCD” B = “ACD”，返回 true；
给出 A = “ABCD” B = “AABC”，返回 false。

注意
在 A 中出现的 B 字符串里的字符不需要连续或者有序。

English Version:

Compare two strings A and B, determine whether A contains all of the characters in B.
The characters in string A and B are all Upper Case letters.

Example
For A = “ABCD”, B = “ACD”, return true.
For A = “ABCD”, B = “AABC”, return false.

Note
The characters of B in A are not necessary continuous or ordered.

public class Solution {    /**     * @param A : A string includes Upper Case letters     * @param B : A string includes Upper Case letter     * @return :  if string A contains all of the characters in B return true else return false     */    public boolean compareStrings(String A, String B) {        if(A.length() < B.length()) return false;        Map<Character, Integer> map = new HashMap<Character, Integer>();        for(int i = 0; i < A.length(); i++) {            char c = A.charAt(i);            if(map.containsKey(c)) {                int value = map.get(c);                map.put(c, ++value);            }else {                map.put(c, 1);            }        }        for(int i = 0; i < B.length(); i++) {            char c = B.charAt(i);            if(map.containsKey(c)) {                int value = map.get(c);                if(--value < 0) return false;                map.put(c, value);            }else {                return false;            }        }        return true;    }}

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