uva 11462 - Age Sort

11462 - Age Sort

You are given the ages (in years) of all people of a country with at least 1 year of age. You know thatno individual in that country lives for 100 or more years. Now, you are given a very simple task of

sorting all the ages in ascending order.

Input

There are multiple test cases in the input le. Each case starts with an integer n (0 < n  2000000), the
total number of people. In the next line, there are n integers indicating the ages. Input is terminated
with a case where n = 0. This case should not be processed.
Output
For each case, print a line with n space separated integers. These integers are the ages of that country
sorted in ascending order.
Warning: Input Data is pretty big ( 25 MB) so use faster IO.
Sample Input
5
3 4 2 1 5
5
2 3 2 3 1
0
Sample Output
1 2 3 4 5

1 2 2 3 3

题意：

给定你一组年龄，要你按从小到大排序。

思路：

用sort()函数进行排序即可。

#include<iostream>#include<cstdio>#include<algorithm>using namespace std;const int maxn=2000000;int  a[maxn];int main(){    int n;    while(cin>>n&&n!=0)    {        for(int i=0;i<n;i++)          cin>>a[i];            sort(a,a+n);        for(int i=0;i<n-1;i++)           cout<<a[i]<<' ';           cout<<a[n-1];           cout<<endl;    }    return 0;}