嘻唰唰第一批之对象的转换

来源：互联网发布：微信开发团队知乎编辑：程序博客网时间：2024/04/29 10:27

代码

#include <iostream>#include<cstring>#include<iomanip>#include<cstdio>using namespace std;class Student{    int num;    char *name;    char sex;    float score;public:    Student(int nu,char *na,char a,float s=0):num(nu),sex(a),score(s)    {        name=new char[strlen(na)+1];        strcpy(name,na);    }    void display()    {        cout<<"num:"<<num<<endl<<"name"<<":"<<name;        cout<<endl<<"sex:"<<sex<<endl<<"score:"<<score<<endl;    }    friend class Teacher;};class Teacher{    int num;    char *name;    char sex;    float pay;public:    Teacher(int nu,char *na,char a,float p):num(nu),sex(a),pay(p)    {        name=new char[strlen(na)+1];        strcpy(name,na);    }    Teacher(Student&s)    {        num=s.num;        name=new char[strlen(s.name)];        strcpy(name,s.name);        sex=s.sex;    }    void setpay(float n)    {        pay=n;    }    void display()    {        cout<<"num:"<<num;        cout<<endl<<"name:"<<name<<endl;        cout<<"sex:"<<sex<<endl<<"pay:"<<pay<<endl;    }};int main(){    cout<<setiosflags(ios::fixed);    cout<<setprecision(2);    int num;    char name[20];    char sex;    float score;    float pay;    cin>>num>>name>>sex>>pay;    Teacher teacher1(num,name,sex,pay);    cin>>num>>name>>sex>>score;    Student student1(num,name,sex,score);    cout<<"student1:"<<endl;    student1.display();    Teacher teacher2=Teacher(student1);    teacher2.setpay(1500);    cout<<"teacher2:"<<endl;    teacher2.display();    return 0;}

总结：

但是不知道脑子抽的什么风，就写了中间位置的一个参数赋初值，结果老是错错错，可怜我还愣是不知道哪儿错了，唉。。。。。

结果是因为这个。。。后面带实参的话会有些问题，若实参数目不足，只会是最后一个形参接收不到实参，而形参列表里又没有初始化，就没有值
public:
Student(int nu=1,char *na,char a,float s=0)

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