Codeforces 560B Gerald is into Art(构造性算法)

B. Gerald is into Art

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought a special board to attach it to the wall and place the paintings on the board. The board has shape of an a1 × b1 rectangle, the paintings have shape of a a2 × b2 and a3 × b3 rectangles.

Since the paintings are painted in the style of abstract art, it does not matter exactly how they will be rotated, but still, one side of both the board, and each of the paintings must be parallel to the floor. The paintings can touch each other and the edges of the board, but can not overlap or go beyond the edge of the board. Gerald asks whether it is possible to place the paintings on the board, or is the board he bought not large enough?

Input

The first line contains two space-separated numbers a1 and b1 — the sides of the board. Next two lines contain numbers a2, b2, a3 and b3— the sides of the paintings. All numbers ai, bi in the input are integers and fit into the range from 1 to 1000.

Output

If the paintings can be placed on the wall, print "YES" (without the quotes), and if they cannot, print "NO" (without the quotes).

Sample test(s)

input

3 21 32 1

output

YES

input

5 53 33 3

output

NO

input

4 22 31 2

output

YES

题意：

先给出一组a*b，表示a*b面积大小的木板，再给出两组a1*b1，a2*b2，表示两幅画的面积大小。两幅画放在木板上，不能超出木板界限，画不能重叠。问能否成功放置。注意a>b时要交换。要把所有情况考录清楚就ok。

代码:

#include<iostream>using namespace std;int main(){    int a,b,a1,a2,b1,b2;    cin>>a>>b;    int s=a*b;    cin>>a1>>b1;    int s1=a1*b1;    cin>>a2>>b2;    int s2=a2*b2;    if(s<s1+s2)    {        cout<<"NO"<<endl;        return 0;    }    if(a>b)    {        int t=a;        a=b;        b=t;    }    if(a1>b1)    {        int t=a1;        a1=b1;        b1=t;    }    if(a2>b2)    {        int t=a2;        a2=b2;        b2=t;    }    if(b1>b||b2>b)    {        cout<<"NO"<<endl;        return 0;    }    if(a1>a||a2>a)    {        cout<<"NO"<<endl;        return 0;    }    if(a1+a2<=a)    {        cout<<"YES"<<endl;        return 0;    }    if(a1==a)    {        if(b1+b2<=b)        {            cout<<"YES"<<endl;            return 0;        }        else if(b-b1>=a2&&a>=b2)        {            cout<<"YES"<<endl;            return 0;        }        else        {            cout<<"NO"<<endl;            return 0;        }    }    if(a2==a)    {        if(b1+b2<=b)        {            cout<<"YES"<<endl;            return 0;        }        else if(b-b2>=a1&&a>=b1)        {            cout<<"YES"<<endl;            return 0;        }        else        {            cout<<"NO"<<endl;            return 0;        }    }    if(b-b1>=a2 && b2<=a)    {        cout<<"YES"<<endl;        return 0;    }    if(a-a1>=a2 && b2<b)    {        cout<<"YES"<<endl;        return 0;    }    if(a>=b1)    {        if(b-a1>=a2&&a>=b2)        {            cout<<"YES"<<endl;            return 0;        }        if(a-b1>=a2 && b2<=b)        {            cout<<"YES"<<endl;            return 0;        }    }    cout<<"NO"<<endl;    return 0;}