一个简单的多线程题目

来源：互联网发布：华为it应用技术工程师编辑：程序博客网时间：2024/05/22 11:06

今天看到一个简单的多线程题目，自己写了一下，功能基本实现，如有问题还望指出交流；

题目：编写一个程序，开启3个线程，这3个线程的ID分别为A、B、C，每个线程将自己的ID在屏幕上打印10遍，要求输出结果必须按ABC的顺序显示；如：ABCABC….依次递推。

// TEST-3.cpp : 定义控制台应用程序的入口点。//#include "stdafx.h"#include <Windows.h>#include <process.h>CRITICAL_SECTION g_cs; //题目较简单，没有用到临界区HANDLE g_SemaphoreA,g_SemaphoreB,g_SemaphoreC;int g_nNum = 0;bool g_bFlag = true;unsigned int __stdcall FunA(PVOID pPm){while(g_bFlag){WaitForSingleObject(g_SemaphoreA,INFINITE);if (g_nNum ==10){ReleaseSemaphore(g_SemaphoreA,1,NULL);ReleaseSemaphore(g_SemaphoreB,1,NULL);ReleaseSemaphore(g_SemaphoreC,1,NULL);g_bFlag = false;break;}else++g_nNum;printf("A：第%d次打印，ID%d\r\n",g_nNum,GetCurrentThreadId());ReleaseSemaphore(g_SemaphoreB,1,NULL);Sleep(10);}return  0;}unsigned int __stdcall FunB(PVOID pPm){while(g_bFlag){WaitForSingleObject(g_SemaphoreB,INFINITE);printf("B：第%d次打印，ID%d\r\n",g_nNum,GetCurrentThreadId());ReleaseSemaphore(g_SemaphoreC,1,NULL);Sleep(10);}return  0;}unsigned int __stdcall FunC(PVOID pPm){while(g_bFlag){WaitForSingleObject(g_SemaphoreC,INFINITE);printf("C：第%d次打印，ID%d\r\n",g_nNum,GetCurrentThreadId());ReleaseSemaphore(g_SemaphoreA,1,NULL);Sleep(10);}return  0;}int _tmain(int argc, _TCHAR* argv[]){g_SemaphoreA = CreateSemaphore(NULL,1,3,NULL);g_SemaphoreB = CreateSemaphore(NULL,0,3,NULL);g_SemaphoreC = CreateSemaphore(NULL,0,3,NULL);InitializeCriticalSectionAndSpinCount(&g_cs,4000);HANDLE hThread[3];hThread[0]=(HANDLE)_beginthreadex(NULL,0,FunA,NULL,0,NULL);hThread[1]=(HANDLE)_beginthreadex(NULL,0,FunB,NULL,0,NULL);hThread[2]=(HANDLE)_beginthreadex(NULL,0,FunC,NULL,0,NULL);WaitForMultipleObjects(3,hThread,TRUE,INFINITE);CloseHandle(g_SemaphoreA);CloseHandle(g_SemaphoreB);CloseHandle(g_SemaphoreC);DeleteCriticalSection(&g_cs);for (int i = 0 ;i<3;++i){CloseHandle(hThread[i]);}return 0;}

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