zoj3191 Strange Clock（水题，但为何是wrong answer？？？）

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Strange Clock

Time Limit: 1000MS Memory Limit: 32768KB 64bit IO Format: %lld & %llu

Submit Status

Description

There is a strange clock, without any number written. Can you tell me what time it is now, based on the angle of the hour hand?

When the hour hand points right (0 degree), it is 3 o'clock. When it points to 80 degrees, it's between 0 o'clock and 1 o'clock. Note that there is no 12 o'clock. You should always write 0 o'clock instead.

Input

There are at most 10 test cases. Each case contains a single integer a (0 <= a < 360), the angle of the hour hand. The input ends with a = -1.

Output

For each test case, print the current time, in one of the following format:

- Exactly x o'clock- Between x o'clock and y o'clock

Note that, in the second format, x o'clock should be exactly one hour before y o'clock, So you cannot write something like "Between 3 o'clock and 2 o'clock".

Sample Input

90245-1

Sample Output

Exactly 0 o'clockBetween 6 o'clock and 7 o'clock

Source

The 34th ACM-ICPC Asia Regional 2009 Ningbo Site NIT Cup National Invitation Contest

分析：

水题。我的代码：（查了好久，一直返回wrong answer）

#include <iostream>
#include<cstdio>
using namespace std;

int main()
{
    int a;
    int x,y;
    while(scanf("%d",&a)&&a!=-1)
    {
        if(a<90)
        {
            if(a%30==0)
            {
                x=3-a/30;
                printf("Exactly %d o'clock\n",x);//用转义字符/'也不行
            }
            else
            {
                y=3-a/30;
                x=y-1;
                printf("Between %d o'clock and %d o'clock\n",x,y);
            }
        }
        else if(a==90)
        {
            printf("Exactly 0 o'clock\n");
        }
        else
        {
            if(a%30==0)
            {
                x=12-(a-90)/30;
                printf("Exactly %d o'clock\n",x);
            }
            else
            {
                x=12-(a-90)/30-1;
                y=x+1;
                printf("Between %d o'clock and %d o'clock\n",x,y);
            }
        }
    }
    return 0;
}

ac代码：

#include <stdio.h>int main(void){    int a;        while (scanf("%d", &a) != EOF && a != -1)    {        if (a % 30 == 0)            printf("Exactly %d o'clock\n", (15 - a/30) % 12);        else            printf("Between %d o'clock and %d o'clock\n", (15 - a/30 - 1) % 12, (15 - a/30) % 12);    }        return 0;}

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