杭电OJ-1073_Online Judge

Online Judge

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 6197    Accepted Submission(s): 2321

Problem Description

Ignatius is building an Online Judge, now he has worked out all the problems except the Judge System. The system has to read data from correct output file and user's result file, then the system compare the two files. If the two files are absolutly same, then the Judge System return "Accepted", else if the only differences between the two files are spaces(' '), tabs('\t'), or enters('\n'), the Judge System should return "Presentation Error", else the system will return "Wrong Answer".

Given the data of correct output file and the data of user's result file, your task is to determine which result the Judge System will return.

题意：

比较两个字符串，

      完全一样输出Accepted

      除去‘ ’ ， ‘\t’，‘\n',其它都一样输出Presentation Error

      else 输出 Wrong Answer

要点：

    1.字符串的输入循环的跳出判断（’ ‘，’\t‘，’\n' 都不跳过），

    2.data部分的截取（因为输入格式都一样，不截取也可以，只不过耗时多一些）

#include<iostream>#include<string>using namespace std;int T,i,j;char a[5000], b[5000];bool flag1, flag2;//flag1答案正确（true代表错误），flag2格式正确（true代表错误）int input(char *a){int i = 0;while (true){a[i] = cin.get();if (a[i - 3] == '\n'&&a[i - 2] == 'E'&&a[i - 1] == 'N'&&a[i] == 'D')  //当'\n','E','N','D'相连时跳出循环break;i++;}return i;}void judge(){for (int x = 5, y = 5; x < i-2 || y<j-2;){if (a[x] == b[y]){x++;y++;}else if (a[x] == ' ' || a[x] == '\t' || a[x] == '\n'){x++;flag2 = true;}else if (b[y] == ' ' || b[y] == '\t' || b[y] == '\n'){y++;flag2 = true;}else{flag1 = true;break;}}}int main(void){cin >> T;while (T--){flag1 = false, flag2 = false;i = input(a);j = input(b);judge();if (flag1)cout << "Wrong Answer" << endl;else{if (flag2)cout << "Presentation Error" << endl;elsecout << "Accepted" << endl;}}return 0;}