关于C++虚函数和纯虚函数

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直接上代码

第一种情况：

#include <iostream>using namespace std;class CPureVirtual{public:    virtual void func() = 0;};class CVirtual : public CPureVirtual{public:    void func()    {        cout<<"CVirtual::func()"<<endl;    }};class CInstance : public CVirtual{public:    void func()    {        cout<<"CInstance::func()"<<endl;    }};int main(){    CInstance in;    CVirtual *pVirt = &in;    pVirt->func();    return 0;}

输出

输出：CInstance::func()

第二种情况：

#include <iostream>using namespace std;class CPureVirtual{public:    virtual void func() = 0;};class CVirtual/* : public CPureVirtual*/{public:    void func()    {        cout<<"CVirtual::func()"<<endl;    }};class CInstance : public CVirtual{public:    void func()    {        cout<<"CInstance::func()"<<endl;    }};int main(){    CInstance in;    CVirtual *pVirt = &in;    pVirt->func();    return 0;}

输出：CVirtual::func()

第三种情况：

#include <iostream>using namespace std;class CPureVirtual{public:    virtual void func() = 0;};class CVirtual/* : public CPureVirtual*/{public:    virtual void func()    {        cout<<"CVirtual::func()"<<endl;    }};class CInstance : public CVirtual{public:    void func()    {        cout<<"CInstance::func()"<<endl;    }};int main(){    CInstance in;    CVirtual *pVirt = &in;    pVirt->func();    return 0;}

输出：CInstance::func()

好吧，从代码和输出结果已经看出不同了，自己体会吧。

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