Search Insert Position

题目：

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0

思想：

采用二分查找法

代码：

class Solution {public:    int searchInsert(vector<int>& nums, int target) {        int length = nums.size();int begin = 0;int end = length - 1;while (begin <= end){int middle = (begin + end) >> 1;if (nums[middle] == target)return middle;else if (nums[middle] < target){begin = middle + 1;}elseend = middle - 1;}if (begin>end){return begin;}    }};