南邮 OJ 1199 B_Conversions

B_Conversions

时间限制(普通/Java) : 1000 MS/ 3000 MS          运行内存限制 : 65536 KByte
总提交 : 47            测试通过 : 22 

比赛描述

Conversion between the metric and English measurement systems is relatively simple. Often, it involves either multiplying or dividing by a constant. You must write a program that converts between the following units:

输入

The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.

Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. The unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.

输出

For each dataset, you should generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and the appropriately converted value rounded to 4 decimal places, a space and the unit specification for the converted value.

样例输入

5
1 kg
2 l
7 lb
3.5 g
0 l

样例输出

1 2.2046 lb
2 0.5284 g
3 3.1752 kg
4 13.2489 l
5 0.0000 g

题目来源

Greater New York Region 2007

#include<iostream>#include<iomanip>#include<string>using namespace std;int main(){int N,i;double d;string s;cin>>N;cout<<fixed<<setprecision(4);for(i=1;i<=N;i++){cin>>d>>s;cout<<i<<' ';if("kg"==s){cout<<d*2.2046<<" lb"<<endl;}else if("lb"==s){cout<<d*0.4536<<" kg"<<endl;}else if("l"==s){cout<<d*0.2642<<" g"<<endl;}else if("g"==s){cout<<d*3.7854<<" l"<<endl;}}}