LeetCode #27 Remove Element
来源:互联网 发布:北斗cors站数据下载 编辑:程序博客网 时间:2024/06/08 05:36
class Solution: # @param {integer[]} nums # @param {integer} val # @return {integer} def removeElement(self, nums, val): size = 0 for i in range(0,len(nums)): if nums[i] != val: size+=1 j = 0 for i in range(size,len(nums)): if nums[i] != val: while nums[j] != val: j+=1 nums[j] = nums[i] nums[i] = val return size
0 0
- LeetCode(27)Remove Element
- [leetcode 27] Remove Element
- [leetcode 27] Remove Element
- [Leetcode] 27 - Remove Element
- leetcode|27|Remove Element
- LeetCode | #27 Remove Element
- LeetCode 27 : Remove Element
- LeetCode 27 Remove Element
- leetcode-27 Remove Element
- leetcode 27 Remove Element
- LeetCode 27 Remove Element
- LeetCode 27 Remove Element
- leetcode-27 Remove Element
- #27 Remove Element leetcode
- LeetCode---(27) Remove Element
- Leetcode 27 Remove Element
- LeetCode 27 - Remove Element
- LeetCode 27:Remove Element
- android常用工具类 -- 打印log日志
- [Leetcode] Reverse Linked List
- ExpandableListView的一些问题
- Linux制作run安装包
- 手机号码替换xx(Java)
- LeetCode #27 Remove Element
- CXF开发webservice需要的最少jar包,CXF发布和调用客户端代码
- hdu4497 lcm and gcd
- 我的核弹C++(一)Void 类型作用
- ASK每周精彩问答 最纯粹的技术分享社区
- WCF REST 工作总结(二)
- mysql explain type
- NUC100RE3AN串口接收程序
- iOS cell(UITableViewCell)自适应布局