不用乘、除、减、平方打印前N个平方数

其实挺简单的一个问题，原题链接：http://www.geeksforgeeks.org/print-squares-first-n-natural-numbers-without-using/

def PrintFirstNSquareNumbers(n):"""Print first n numbers without using *, /, -, ** or powerBy the simple fact that 1 + 3 + ... + 2n-1 = (1 + 2n-1)/2 * n = n^2"""s, x = 0, -1for i in range(n):print(s)x += 2s += x# test casePrintFirstNSquareNumbers(10)